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ANDERSON & ASSOCIATES CONSULTING ENGINEERS,-INC.·ID1 <br />3902 VILLA SANJOSE DRIVE. JACKSONVILLE FLORIDA 32217 (904} 731·7978 FaX (904 731-T771 <br />PERIMETER TRUSS <br />STRUCTURAL CAPACITY <br />D. Determine Truss Shear Capacity (Cont.) <br />1. Check Local Buckling on 1.5" Dia. (1/8" Wall) Diagonal <br />. <br />Ld: <br />26 <br />sin(Od) <br />1dLd=34.517 r2 = 0.488 Therefore:1 =70.711 <br />r2 <br />A.2 = 0.54 Fal := 20.2 - 0.126.2 <br />r2 <br />51000 <br />Fa2:= Ed)2 Fa := ifl ·M<66, Fal, Fa Fa = 10.24 r2 <br />1-1(r2 /Fa = 12 ksi (Weld Affected Zone) <br />Determine Allowable Force in Diagonal <br />Pd:= if(Fa< 12,Fa·Al, 12-A2)Pd = 5.508 kips <br />2. Check Weld Between Diagonal and Chord Member <br />Determine Length of Weld: <br />Idd:= 1.5 D:= 2 ed = 0.853 0 := asin' iiiA 2 ¢ = 1.696a:= f -csc(ed)a = 0.996 <br />U <br />b = 0.8484 <br />Lw:= a+b+3 .PU._Lw,v 5.767 Where:tw := 0.1875 3/16"Weld <br />Determine Allowable Force At Diagonal Member <br />Fw:= 5 ksi (Allowable Stress at Weld) <br />Pdw := Fw -Lw ·0.707 ·tw Pdw = 3.823 - kips Controls <br />3. Check Misnoding at End of Truss <br />Misnoding at End of Truss causes local bending on the Chord Member <br />Fbc:= 14.0 ksi (Extreme Fiber Allowable Compression Stress) <br />Fbt:= 13.5 ksi (Extreme Fiber Allowable Tension Stress)Controls <br />SI : <br />I 1 <br />- S 1 = 0.325 in3 Therefore:Ma := Fbt·SI Ma = 4388 in-kips(Dl) <br />42, <br />rruiend := 1.00 in. (Misnoding at End of Truss)M:= Ma <br />MPdnin:=idmn = 5.825 kipsmnend·sin(Od)