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Base Plate Analysis: 1 The base plate will be analyzed with the rectangular stress resulting from the vertical load P, combined with the triangular stresses resulting from the moment Mb (if any). Three criteria are used in determining Mb: 1. Moment capacity of the base plate 2. Moment capacity of the anchor bolts 3. Vcol . h/2 (full fixity) Mb is the smallest value obtained from these three criteria. Fy = 36000 psi Pcol = 18186 lbs MBase = 8096 in-lbs P/A = Pcol/(D . B) = 18186 / (7.87 . 7.87) = 293 psi fb = MBase / (D . B2 / 6) = 8096 / (7.87 . 7.872 / 6) = 99.5 psi fb2 = fb . (2 . b1 / B) = 99.5 . (2 . 2.44/7.87) = 61.59 psi fb1 = fb - fb2 = 99.5 - 61.59 = 37.91 psi Mb = wb1 2 / 2 = (b1 2 / 2) . (fa + fb1 + 0.67 . fb2) = (2.442 / 2) . (293 + 37.91 + 0.67 . 61.59) = 1105.53 in-lbs SBase = (B . t2) / 6 = 0.2sq.in. FBase = 0.9 . Fy = 32,400 psi fb / Fb = Mb / (SBase . FBase) = 1105.53 / (0.2 . 32,400) = 0.17 Plate width B =7.87 in. Plate depth D =7.87 in. Plate thickness t =0.39 in. Column width b =3 in. Column depth d =2.72 in. b1 =2.44 in. Sx =6.25 in. Sy =6.25 in. TTotal =7,164 lbs. Te =0.37 in. Base Plate Tension analysis per ACI318-14 17.2.3.4.3 (b), ductile yield of base plate Lw = (Sx - b) / 2 = 1.63 in. Ld = (Sy - b) / 2 = 1.77 in. Moment Arm (L) = Max(Lw,Ld) = 1.77 in. Manchor = TTotal / 2 . L = 6327.6 in-lbs S = B . t2/6 = 0.176in3 Mbaseplate = S . Fy = 6,328 in-lbs fMbaseplate = 0.9 . Mn = 5,695 in-lbs fMbaseplate < Manchor , Base plate will yield first. Since the base plate will yield before anchor getting full tension capacity, over-strength factor is not applicable. PROJECT: FOR: ADDRESS: SHEET#: CALCULATED BY: DATE: Pace Supply The Beacon Group_Kevin 3421 W. Segerstro Santa Ana, CA 25 tchang 6/20/2023 TEL:(909)869-0989 1130 E. CYPRESS ST, COVINA, CA 91724 PN:20230619_19 3421 W Segerstrom Ave - 10111647610/31/2023