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Project <br />1011 <br />Job Ref. <br />Section <br />LINE-A <br />Sheet no./rev. <br /> 4 <br />Calc. by <br />N.K <br />Date <br />15/11/2024 <br />Chk'd by Date App'd by Date <br />Load combination 2 <br />Shear force for maximum compression;V = 0.7  Eq = 1.535 kips <br />Axial force for maximum compression;P = ((D + Swt  h) + 0.7  0.2  SDS  (D + Swt  h))  s / 2 + -1  0.7  Eq_ch1 <br />= 0.546 kips <br />Maximum compressive force in chord;C = V  h / beff + P = 1.268 kips <br />Maximum applied compressive stress;fc = C / Ae = 103 lb/in2 <br />Design compressive stress;Fc' = Fc  CD  CMc  Ctc  CFc  Ci  CP = 552 lb/in2 <br />fc / Fc' = 0.187 <br />PASS - Design compressive stress exceeds maximum applied compressive stress <br />Design bearing compr. stress, bottom plate;Fc_perp' = Fc_perp  CMc  Ctc  Ci  Cb = 625 lb/in2 <br />fc / Fc_perp' = 0.166 <br />PASS - Design bearing compressive stress exceeds maximum applied bearing compressive stress <br />Chord capacity for chord 2 <br />Load combination 6 <br />Shear force for maximum tension;V = 0.7  Eq = 1.535 kips <br />Axial force for maximum tension;P = (0.6  (D + Swt  h) - 0.7  0.2  SDS  (D + Swt  h))  b1 / 2 + -1  0.7  <br />Eq_ch2 = 0.305 kips <br />Maximum tensile force in chord;T = V  h / beff - P = 0.417 kips <br />Maximum applied tensile stress;ft = T / Aen = 41 lb/in2 <br />Design tensile stress;Ft' = Ft  CD  CMt  Ctt  CFt  Ci = 1380 lb/in2 <br />ft / Ft' = 0.030 <br />PASS - Design tensile stress exceeds maximum applied tensile stress <br />Load combination 2 <br />Shear force for maximum compression;V = 0.7  Eq = 1.535 kips <br />Axial force for maximum compression;P = ((D + Swt  h) + 0.7  0.2  SDS  (D + Swt  h))  s / 2 + 0.7  Eq_ch2 = <br />0.504 kips <br />Maximum compressive force in chord;C = V  h / beff + P = 1.226 kips <br />Maximum applied compressive stress;fc = C / Ae = 100 lb/in2 <br />Design compressive stress;Fc' = Fc  CD  CMc  Ctc  CFc  Ci  CP = 552 lb/in2 <br />fc / Fc' = 0.181 <br />PASS - Design compressive stress exceeds maximum applied compressive stress <br />Design bearing compr. stress, bottom plate;Fc_perp' = Fc_perp  CMc  Ctc  Ci  Cb = 625 lb/in2 <br />fc / Fc_perp' = 0.160 <br />PASS - Design bearing compressive stress exceeds maximum applied bearing compressive stress <br />Hold down force <br />Chord 1;T1 = 0.458 kips <br />Chord 2;T2 = 0.417 kips <br />Wind load deflection <br />Design shear force;Vw = fWserv  W = 1.2 kips <br />Deflection limit;w_allow= h / 500 = 0.2 in <br />Induced unit shear;vw = Vw / b = 66.08 lb/ft <br />Anchor tension force;T = max(0 kips,vw  h  b / beff - 0.6  (D + Swt  h)  b / 2 + 0.6  <br />max(abs(W ch1),abs(W ch2))) = 0.000 kips <br />Page 49 of 108 <br />1011 W Second St <br />5/1/2025