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D. Electrical Calculations <br />1. PV Circuit current <br />PV circuit nominal current <br />Continuous current adjustindnt factor <br />PV circuit continuous current rating <br />9.9 'amps <br />125% <br />12.375 amps <br />2013 CE€ Arricle 7(15.611(13)) <br />2. Overcurrent protection device rating <br />PV circuit continuous curt-chr rating <br />Next.standard size fuse/breaker to protect coriductots <br />12375 amps <br />15l amp breaker <br />Use 15 amp AC rated fuse or breaker <br />3. Conductor conditions of use adjustment (conductor ampacity derate) <br />a. Temperature adder <br />Average high temperature 40'9°C (105.62 °F) <br />Conduit is installed 1 " above the roof surface Add 22 °C to ambient <br />,Adjusted maximum ambient remperacure 62.9 °C (145.22°19 <br />2013 CEC Table 310. I 5(B)(2)(a) <br />b. PV Circuit current adjustment for new ambient temperature <br />Derate factor for 62.9 °C (145.22°F)58% <br />Adjusted PV circuit continuous current 243 amps <br />2013 CE¢Table 310.16 (bottom of rable) <br />c. PV Circuit current adjustment for conduit fill <br />Number of current-carr·ing conducrors <br />Conduit fill derate factor <br />Final Adjusted PV circuit continuous cufrent <br />6 conductors <br />80°k <br />26.6 amps <br />2013 CEC Table 31 0.15(13)(2)(1) <br />Total derated ampacity; for PV circuit 26.6 ami?s <br />Conductors (tag2 on 1-line) must be rated for a minimum of 26.6 amps <br />THWN-2 (90 °C) #12AWG conductor is rated for 3Qi amps (Use #12AWG or larger)2013 CEC Table 310.16 <br />4. Voltage drop (keep below 3% total) <br />2 pEaks: <br />1. Voltage drop across longest PV circuit micre-inverters (fr(·mi modules to inbox) <br />2. Voltage drop across A C conductors (from j-box to poinc of interconnection) <br />1. Mirco-inverter:voltage drop: <br />The largest nornber of micro-i'nvercers in a row in the entire arrayis 4 inCitcuit: 1. According to <br />manufacturer's specifications ihis equals a voltage drop ot- 0.09 °4. <br />0.09% <br />2. AC conductor voltage drop: <br />= I x R x D (+ 240 x 100 to conveut to percent) <br />= (Nominal current of largest circuit) r (Resistance of #12AWG copper) x (Total wird ruh) <br />= (Circuit 1 nominal current is 9.9 i mps) x (0.002019) x (232) + (240 vojt© x (100)1.92%, <br />Total system voltage drop:2.01% <br />-vivint 90. 4 <br />. <br />-- <br />-