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, ROJECT: UNIT # 1 (650 LBS)PAGE: <br />CLIENT: DESIGN BY: <br />JOB NO. : , .DATE:REVIEW BY: <br />E¢iflifim®f*158.1**gattiEYM¢R[dIR®fil :..:i.hi,#:184:-14*Z'·5· .·.1' f·jrj "'-r 79···p·- <br />INPUT DATA & DESIGN SUMMARY <br />LAG SCREW DIAMETER <br />4 ft,· i <br />b <br />1/2 " lA, i ·p,· 4·:S i <br />Long 4 in,I.1/3 Fb LAG SCREW LENGTH 6FP <br />kipsEQUIPMENT WEIGHT W = 0.65 <br />CM HEIGHT H = 1.50 ft, 2/3 total height I <br />ANCHORAGE LENGTH , LAG SCREWS ALONG L EDGE <br />LAG SCREW SPACING L I <br />L 4 ft <br />NL 3 per line <br />L/(NL-1)=24 in <br />B 4 ft <br />NB 2 per line <br />:B/(Ne -1)=48 in <br />ELEVATION <br />ANCHORAGE WIDTH <br />LAG SCREWS ALONG B EDGI <br />LAG SCREW SPACING Se . <br />L <br />/4-• eons per l,™ <br />[THE ANCHORAGE, USING 1/2" x 4" LAG SCREWS, IS ADEQUATE.]t +++++++4+ <br />-§44 <br />mANALYSIS + <br />ALLOWABLE TENSION & SHEAR VALUES + <br />Zll' = Co Cd Cg ZII =252 lbs +++++++++t <br />where Co =1.6 (NDS Tab 2.3.2) . <br />Cd=(8D) =0.814 - PLAN <br />p =S+ (T-E) - (Diaphragm Thk) -ts=3.256 in <br />S + (T-E) =3.688 in (NDS Appendix L2) <br />Diaphragm Thk = '0.298 ' in (0.298 for 15/32,0.319 for 19/32, UBC Table 23-2-H, page 3-420) <br />ts.0.134 . in (10 gage, NDS Tab 11 K) <br />Cg = 0.92 (NDS 10.3.6) <br />Zii = 210 lbs (NDS Tab 11 K) <br />Zp' = CD Cd Cg ZY 168 lbs <br />Z¥ =140 lbs (NDS Tab 11 K) <br />(W' p) = CD W (T-E) =1323 lbs <br />where W =378 lbs / in <br />(TIE) =2.188 in · <br />DESIGN LOADS <br />FH=F p = (KH) MAX{ 0.3SDS'p\AL MIN[ 0.4apSos'p(1+2z/h)/Rp <br />= 1 MAX{ 0.45W, MIN[ 1.OOW, 2.40W ]} <br />= 1.00 W, (SD) <br />= 0.71 W , (ASD) =0.46 kips <br />W, 1.6Sos'PW ]} 1 <br />where SOS = 1 <br />4- 1.5 <br />ap = 1 <br />Rp = 1.5 <br />Fv=Kv W =0.14 W , (ASD) =0.09 kips, up & down Z=9 R <br />h=12 ft <br />KH = 1 <br />Kv= KH 0.2 Sos/ 1.4 =0.14 <br />MAXIMUM OVERTURNING MOMENT AT ANCHOR EDGE <br />MoT = PH=0.70 ft-kips <br />MRES,l - (09W - Fv) (0.58) = 0.98 ft-lips > <br />MRES,8 - (0·9\Af - Fv) (O.58) = 0.98 ft-kips > <br />Mw no tension anchors. <br />MoT no tension anchors. <br />TENSION LOAD AT CORNER LAG SCREW <br />TL = (Fv -0.9 W) / A +Mory/I= <br />where A = 2(NL + NB) -4 = <br />1 =Exi2= 2304 inK <br />5 lbs / bolt TB = (Fv -0.9 \AD /A+ MoT y/I= <br />6 (total bolts)where I = EYi2 =3456 in <br />·bolts y = 0.5 B = 24 in <br />0 lbs / bolt <br />2-bolts <br />y = 0.5 L = 24 in <br />SHEAR LOAD AT EACH LAG SCREW <br />V=FH/A= 77 lbs / bolt <br />CHECK CORNER SCREW CAPACITY AT COMBINED LATERAL AND WITHDRAWAL LOADS <br />Zo' = Zii'(W p) / (Zo'sirfa + Wp cosa)(NDS 11.4-1) <br />= 252 lbs / bolt >[12 + V 10.5 = 78 lbs /bolt [SATISFACTORY] <br />where a = tan-1(TL / V) =372 0 <br />Zo' = Z.r'(W p) / (4'sinG + Wp Cos2a)(NDS 11.4-1) <br />= 168 lbs /bolt >rr82 + 9 1°·5= 77 lbs/bolt [SATISFACTORY] <br />0where 0 =tan-1(Ta / V) =0.00