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D. Electrical Calculations <br />1. PV Circuit current <br />PV circuit nominal current <br />Continuous cutrent: adj'ustfnent factor <br />PV circuit continuous current rating <br />12,6 amps <br />125% <br />15.75 amps <br />2013 GEC Arlidle 705.60(B)) <br />2. Overcurrent protection device rating <br />PV circuit continuous current rating <br />Next standard size fuse/breaket to protect conductors <br />15.75 amps <br />20 amp breaker <br />Use 20 amp AC rated fuse or breaker <br />3. Conductor conditions of use adjustment (conductor ampacity derate) <br />a. Temperature adder <br />Average high icmperature 40.9 °C (105.62 °19 <br />Cooddit is inst·.il led 1 " above the 1:00 f surfece Add 22 °C to ambient <br />Adjusted maximum ambient temperature 62.9 °C (145.22°F) <br />2013 CEC Table 310.15(B)(2)(a) <br />b. PV Circuit current adjustment for new ambient temperature <br />Derate factor. for 62.9 °C (145.22°p)®% <br />Adjusted PV circuit: continubus current:27.1 amps <br />2013 CEC Table 310.16 (bottom of table) <br />c. PV Circuit current adjustment for conduit fill <br />Number of cur cIi r- carrying conduci·crs <br />Conduit fill derate factor <br />Final Adjusted PV circuit continuous current <br />3 conductors <br />100% <br />27.1 amps <br />2013 CEE Tab le 310:15(B)(2)(a) <br />Total derated ampacity for PV circuit 27.1 amps <br />Conductors (tag2 on 1-line) must be rated for a minimum of 27.·lamps <br />THWN-2(90 °C) #12AWG conductot is rat·c<{ for 30 anips (Use #12AWG or larger)2013 CEC Table 310.16 <br />4. Voltage drop (keep below 3% total) <br />2 parts: <br />:1. Voltage·diop across longest PV circuit nlicro-inverters (from modules to j-box) <br />2. Voltage drop across AC conductors (from j-box to point of interconnection) <br />1. Mirco-inverter voltage drop: <br />The largest number of micro-inverters in a ro-w in the entire array is 8' inCircuit 1. According to <br />manu ficturer's specifications this equals a volt.ige drop of 0.19 %. <br />0.19% <br />2. AC conductor voltage dr0p: <br />= Ix Rx D (+ 24(3 x 100 to convert to percent) <br />= ominal current o flarges, circuit.) x (Resistance of #12AWG copper) x (Total wire run) <br />= (Circuit 1 nominal cu rrent is 12.6 ,ampt) x (0.00201 62) x (1302 + (240 volts) x (100)1.37% <br />Total system voltage drop:1.56% <br />vovint sola 7