Laserfiche WebLink
Shear wall height H = 8 ft <br /> <br /> <br /> <br />Length (ft) Type H/B Concept <br />6.6 Wall 1.21 Shear Wall <br />2 Opening <br />9.6 Wall 0.83 Shear Wall <br />Shear capacity adjustment factor – cl.4.3.5.6 <br />Sum of perforated shear wall segment lengths ∑bi=6.6+9.6=16.2 ft <br />Total area of wall Awall=18.2×8=145.6 ft 2 <br />Total full height sheathed area A fhs=6.6×8+9.6×8=129.6 ft2 <br />Shear capacity adjustment factor (eqn. 4.3 -6) Co = min(Awall/(3×Ao + Afhs), 1.0)= 0.854 <br />Perforated shear wall capacity <br />Maximum shear force under wind loading V w_max=0.6×WL/1000 =0.71 Kips <br />Shear capacity for wind loading V w=(Vn×Co×∑bi/2000) =6.046 Kips <br />ratio V w-max / Vw =0.117 <br />PASS - Shear capacity for wind load exceeds maximum shear force <br />Maximum shear force under seismic loading V s_max=0.7×Eq/1000 =0.988 Kips <br />Shear capacity for seismic loading V s=(Vn×Co×∑bi/(2.8×1000)) =4.318 Kips <br />ratio V s_max / Vs =0.229 <br />PASS - Shear capacity for seismic load exceeds maximum shear force <br />Chord capacity for chord1 <br />Load Combination : 0.6DL - 0.7EQ <br />Maximum tensile force in chord T=256.911 lbs <br />Maximum applied tensile stress f t=T/Aen=25.533 lb/in2 <br />Design tensile stress F t'=Ft×CD×CMt×Ctt×CFt×Ci=1380 lb/in2 <br />Ratio25.53/1380=0.02 <br />PASS - Design tensile stress exceeds maximum applied tensile stress <br />Load Combination : DL + 0.7EQ <br />Maximum compressive force in chord P=1002.158 lbs <br />Maximum applied compressive stress f c=P/Ae=81.809 lb/in2 <br />Design compressive stress F c'=Fc×CD×CMc×Ctc×CFc×Ci×Cp=596.16 <br />lb/in2Ratio81.81/596.16=0.14 <br />PASS - Design compressive stress exceeds maximum applied compressive stress <br />Page 57 of 290