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PROJECT Air Liquide <br />FOR Modula <br />SHEET NO.10 <br />CALCULATED BY RF <br />DATE 2/27/2023 <br />SLAB AND SOIL ANALYSIS <br />The slab is checked for puncture stress. If no puncture occurs the slab is assumed to distribute the load over a <br />larger area of the soil hence, actins as a footing. <br />BASE PLATE <br />DL-total/col =0 lb Weff. =11.8 in <br />Pmax =11,622 lb Deff. =13.8 in <br />a) Puncture:A1 =162.25 in^2 <br />Fpunct =2.66 x (F'c^0.5) <br />=2.66 x (3000 psi)^0.5 <br />=146 psi <br />Apunct =[(Weff.+t/2)+(Deff.+t/2)] x 2 x t <br />=[(11.8 in + 5.5 in/2) + (13.75 in + 5.5 in/2)] x 2 x 5.5 in CONCRETE <br />=342 in^2 t =5.50 in <br />f'c =3,000 psi <br />fv/Fv =P/(Apunct x Fpunct) <br />=11622 lb/[342 in^2 x 146 psi x 0.6]SOIL <br />=0.39 ≤ 1.0 OK fs =1000 psf <br />b) Bearing:Ø=0.6 <br />ØBn =0.85 x Ø x f'c x A1 <br />=248,243 lb <br />Pu / ØBn =11622 lb / 248243 lb <br />=0.05 ≤ 1.0 OK <br />c) Slab: <br />Pn =1.72 [(ks R1/Ec)104+3.6]f't d2 < === Emperical method formula: "Load Carrying Capacity for Concrete <br />=83,620 LB Slabs on Grade." Journal of Structural Engineering, ASCE, January 1997. <br />ks =50 PCI modulus of subgrade reaction <br />R1 =5.9 one-half the width of base plate <br />Ec =3,122,000 PSI modulus of elasticity of concrete <br />f't =1.7 (f'c)^(2/3)tensile strength in flexture of concrete <br />=354 PSI <br />b =[Ecd3/(12(1-μ2)ks)]0.25 <br />=30.68 IN <=== radius of relative stiffness <br />1.5*b =46.02 IN <=== radius of relative curvature <br />2*1.5*b =92.03 IN <=== columns should be no closer than <br />φ =0.6 factor of safety <br />Pa =Pn x φ <br />=50,172 LB <br />Pmax / Pa =0.23 ≤ 1.0 OK <br />MATERIAL HANDLING ENGINEERING <br />TEL: (909) 869-0989 / FAX: (909) 869-0981 <br />INC. <br />SEIZMIC