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1610 E St Andrew Place Unit# 240 - Plan
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1610 E St Andrew Pl Unit# 240
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1610 E St Andrew Place Unit# 240 - Plan
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Last modified
5/8/2026 5:00:09 AM
Creation date
5/8/2026 5:00:04 AM
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Template:
Plan
Permit Number
101126519
Full Address
1610 E St Andrew Pl Unit# 240
Street Number
1610
Street Direction
E
Street Name
St Andrew
Street Suffix
Pl
Unit Number
240
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Wood Beam <br />LIC# : KW-06020694, Build:20.26.01.14 ARDMORE STRUCTURAL ENGINEERING (c) ENERCALC, LLC 1982-2026 <br />DESCRIPTION:Full Length Beam <br />Project File: Collector's Universe Phase 04 TI.ec6 <br />Project Title: <br />Engineer: <br />Project ID: <br />Project Descr: <br />Referenced Design Standard(s) : NDS 2018 <br />Load Combination Set : ASCE 7-22 / IBC 2024 <br />Code References <br />Governing Code : IBC 2021 <br />Material Properties <br />Beam Bracing :Completely Unbraced <br />Allowable Stress Design <br />iLevel Truss Joist <br />MicroLam LVL 1.9 E <br />2,600.0 <br />2,600.0 <br />2,510.0 <br />750.0 <br />1,900.0 <br />965.71 <br />285.0 <br />1,555.0 42.010 <br />Analysis Method : <br />Eminbend - xx ksi <br />Wood Species : <br />Wood Grade : <br />Fb + <br />psi <br />psi <br />Fv psi <br />Fb - <br />Ft psi <br />Fc - Prll psi <br />psiFc - Perp <br />E : Modulus of Elasticity <br />Ebend- xx ksi <br />Density pcf <br />Load Combination :ASCE 7-22 / IBC 2024 <br />3-1.75x18 <br />Span = 20.0 ft <br />1 2 <br /> D(1.653) L(1.316)D(0.05586) L(0.08645) <br />D(0.16) <br />.Applied Loads Service loads entered. Load Factors will be applied for calculations. <br />Beam self weight calculated and added to loading <br />Uniform Load : D = 0.0420, L = 0.0650 ksf, Tributary Width = 1.330 ft, (D+L+Wall) <br />Uniform Load : D = 0.160 k/ft, Extent = 0.0 -->> 11.0 ft, Tributary Width = 1.0 ft, (Wall) <br />Linked Load(s) <br />Beam Headout Beam, Support 1: D = 1.653, L = 1.316 k @ 11 ft from left end of beam <br />.DESIGN SUMMARY Design OK <br />Maximum Bending Stress Ratio Maximum Shear Stress Ratio <br />3-1.75x18 <br />0.213 <br />Section used for this span3-1.75x18 <br />: 10.504 =: 1 <br />Load Combination <br />+D+L +D+L <br />Span # where maximum occurs Span # 1 <br />Location of maximum on span 10.949 ft <br />60.79 psi= <br />2,302.94 psi <br />Section used for this span <br />Span # where maximum occurs <br />Location of maximum on span <br />Span # 1= <br />Load Combination <br />= <br />= <br />= <br />285.00 psi== <br />0.000 ft= <br />= <br />1,161.00 psi <br />Maximum Deflection <br />1688 <br />>=360 <br />646 <br />Ratio =0 >=240 <br />Max Downward Transient Deflection 0.142 in <br />0 <br />Ratio =>=360 <br />Max Upward Transient Deflection 0 in Ratio = <br />Max Downward Total Deflection 0.371 in Ratio =>=240 <br />Max Upward Total Deflection 0 in <br />fb: Actual <br />F'b <br />fv: Actual <br />F'v <br />Span: 1 : L Only <br />n/a <br />Span: 1 : +D+L <br />n/a <br />NDS2018 NDS2018 <br />Page 4 of 4
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