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Project <br />1011 <br />Job Ref. <br />Section <br />LINE-1 <br />Sheet no./rev. <br /> 4 <br />Calc. by <br />N.K <br />Date <br />19/12/2023 <br />Chk'd by Date App'd by Date <br />Shear force for maximum tension;V = 0.7  Eq = 1.35 kips <br />Axial force for maximum tension;P = (0.6  (D + Swt  h) - 0.7  0.2  SDS  (D + Swt  h))  b / 2 = 1.445 kips <br />Maximum tensile force in chord;T = V  h / (Co  bi) - P = -0.609 kips <br />Maximum applied tensile stress;ft = T / Aen = -61 lb/in2 <br />Design tensile stress;Ft' = Ft  CD  CMt  Ctt  CFt  Ci = 1380 lb/in2 <br />ft / Ft' = -0.044 <br />PASS - Design tensile stress exceeds maximum applied tensile stress <br />Load combination 2 <br />Shear force for maximum compression;V = 0.7  Eq = 1.35 kips <br />Axial force for maximum compression;P = ((D + Swt  h) + 0.7  0.2  SDS  (D + Swt  h))  s / 2 = 0.274 kips <br />Maximum compressive force in chord;C = V  h / (Co  bi) + P = 1.110 kips <br />Maximum applied compressive stress;fc = C / Ae = 91 lb/in2 <br />Design compressive stress;Fc' = Fc  CD  CMc  Ctc  CFc  Ci  CP = 552 lb/in2 <br />fc / Fc' = 0.164 <br />PASS - Design compressive stress exceeds maximum applied compressive stress <br />Design bearing compr. stress, bottom plate;Fc_perp' = Fc_perp  CMc  Ctc  Ci  Cb = 625 lb/in2 <br />fc / Fc_perp' = 0.145 <br />PASS - Design bearing compressive stress exceeds maximum applied bearing compressive stress <br />Collector capacity <br /> <br />Collector seismic design force factor;FColl = 1 <br />Maximum shear force on wall;Vmax = max(FColl  Vs_max, Vw_max) = 1.35 kips <br />Uniform shear applied to wall;va = Vmax / (Co  bi) = 100.3 plf <br />Shear resisted by wall segments;vb = va  b / (b1 + b2) = 129.6 plf <br />Maximum force in collector;Pcoll = 0.259 kips <br />Maximum applied tensile stress;ft = Pcoll / (2  As) = 25 lb/in2 <br />Design tensile stress;Ft' = Ft  CD  CMt  Ctt  CFt  Ci = 1380 lb/in2 <br />ft / Ft' = 0.018 <br />PASS - Design tensile stress exceeds maximum applied tensile stress <br />Maximum applied compressive stress;fc = Pcoll / (2  As) = 25 lb/in2 <br />Column stability factor;CP = 1.00 <br />Design compressive stress;Fc' = Fc  CD  CMc  Ctc  CFc  Ci  CP = 2484 lb/in2 <br />Page 40 of 108 <br />1011 W Second St <br />5/1/2025