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D. Electrical Calculations <br />1. PV Circuit current <br />PV circuir nominal current <br />Continuous current adjustment factor <br />PV circuit continuozi: curren[ rating <br />15:.3 amps <br />125% <br />19.125 amps <br />2013 CEC Article 705.60(B)) <br />2. Overcurrent protection device rating <br />PV'circuit continuous current rating <br />Next standard sjze fuse/breaker Ed prorec[ conducroIs <br />'li9.125 amps <br />20 amp breaker <br />Use 20 amp AC rated fuse or breaker <br />3. Conductor conditions of use adjustment (conductor ampacity derate) <br />a. Temperature adder <br />Average high remperature 40.9 '°.C (105.62 °19 <br />Conduit is installed 1"'above the roof surface .Add 22 °C to ambient <br />Adjusted maximum ambient temperature 62.9 °C (145.22°p) <br />2013 CEC Table 310.15(B)®(a) <br />b. PV Circuit current adjustment for new ambient temperature <br />Derate factof for 62.9 ec 045.22°P)58% <br />Adjusted PV circuit continuous current 32.9 amps <br />2013 GEC Table 310.16 (boriom of cble) <br />c. PV Circuit curfent adjustment for conduit fill <br />Number of current-carrying conductors <br />Conduit Till deratle factor <br />Final Adjusied PV circuit continuous current <br />3 cooductors <br />100°Z, <br />32.9 amps <br />2013 GEC Table 310.15(B)(2)00 <br />Total derated ampacity for PV circuit 32.95amps <br />Conductors (tag2 on 1-line) must be rated for a minimum of 32.9 amps <br />THWN-2 (90 °C) #10AWG conduttor is rated for 4.0 amps (Use #10AWG or larger)2013 CECTable 310.16 <br />4. Voltage drop (keep below 3% total) <br />2.porrs: <br />1. Voltage drop across longest PV circuit micro-inverters (from modules to i-box) <br />2. Vo[[age drop across AC conducrors (from j-box co point e finterconneccion) <br />1. Mirco-invertcf voliage drop:0.24% <br />The largest nufnber o f micro-inverrers ina row in theent:ire array is 7 inCircuit 1. According to <br />manufaciurer'.i specifications this equals a foltage drop of 0.24 %. <br />2. AC corductor vololgc drop: <br />= Ix R x D (+ 240 x 100 0 conver[ to percent) <br />= (Nominal current of laogest circui 0 x (Resistance of #10AWG coppet) x (Total wire run) <br />= f.Circu.it 1 norninal current is 13.3 , nps) x (0.00126@x (1 305 + @40 volts) x BOO)1.04% <br />Total system voltage drop:1.28% <br />Vivint -1.- EA